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MHT CET 2026 (18 Apr, Shift 2) · Junction Transistor

Junction Transistor question from MHT CET 2026 (18 Apr, Shift 2)

Q12MHT CET 2026 · 18 APR · SHIFT 2Medium

Junction Transistor

In an NPN transistor, the collector current is 28 mA. If 80% electrons reach the collector, its base current in mA is

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Answer: (a)

  1. IC=0.8 IE⇒IE=280.8=35I_C = 0.8\,I_E \Rightarrow I_E = \dfrac{28}{0.8} = 35 mA.
  2. IB=IE−IC=35−28=7I_B = I_E - I_C = 35 - 28 = 7 mA.
  3. So the answer is (a) 77 mA.
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