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JEE Main 2026 (22 Jan, Shift 2) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from JEE Main 2026 (22 Jan, Shift 2)

Q11JEE Main 2026 · 22 JAN · SHIFT 2Medium

Organ Pipes & Resonance Tube

In an open organ pipe ν3\nu_3 and ν6\nu_6 are 33rd and 66th harmonic frequencies, respectively. If ν6−ν3=2200 Hz\nu_6 - \nu_3 = 2200\text{ Hz} then length of the pipe is ______ mm.

(Take velocity of sound in air is 330 m/s330\text{ m/s}.)

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Answer: (b)

  1. Open pipe: νn=nv2L\nu_n = \frac{nv}{2L}.
  2. ν6−ν3=3v2L=2200\nu_6 - \nu_3 = \frac{3v}{2L} = 2200
  3. L=3×3302×2200=0.225 m=225 mmL = \frac{3 \times 330}{2 \times 2200} = 0.225\text{ m} = 225\text{ mm}
  4. So the answer is (b) 225.
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