In an optical instrument- microscope, the wavelength of light used are λ₁ = 6800 Å and λ₂ = 5100 Å. The ratio of the resolving power of microscope corresponding to ' λ₁ ' to that for ' λ₂ ' is (a) 9: 16 (b) 5: 4 (c) 4: 3 (d) 3: 4

Answer: (d). Resolving power ∝ (1)/(λ). (RP₁)/(RP₂) = (λ₂)/(λ₁) = (5100)/(6800) = 3/4 So the answer is (d) 3:4.

In an optical instrument- microscope, the wavelength of light used… | MHT CET 2026 (18 Apr, Shift 2)

Q6MHT CET 2026 · 18 APR · SHIFT 2Easy

Resolving Power

In an optical instrument- microscope, the wavelength of light used are $\lambda_1 = 6800$ Å and $\lambda_2 = 5100$ Å. The ratio of the resolving power of microscope corresponding to ' $\lambda_1$ ' to that for ' $\lambda_2$ ' is

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Answer: (d)

Resolving power $\propto \dfrac{1}{\lambda}$ .
$\dfrac{RP_1}{RP_2} = \dfrac{\lambda_2}{\lambda_1} = \dfrac{5100}{6800} = \dfrac{3}{4}$
So the answer is (d) $3:4$ .

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