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MHT CET 2021 (23 Sep, Shift 1) · Biprism, Thin Films & Other Devices

Biprism, Thin Films & Other Devices question from MHT CET 2021 (23 Sep, Shift 1)

Q23MHT CET 2021 · 23 SEP · SHIFT 1Medium

Biprism, Thin Films & Other Devices

In biprims experiment, the $4$ th dark band is formed opposite to one of the slits. The wavelength of light used is $(d =$ distance between the slits, $D =$ distance between scource and the screen)

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Answer: (b)

Point opposite a slit: $y = \frac{d}{2}$ , path difference $= \frac{d^2}{2D}$ .
4th dark band: $\frac{d^2}{2D} = \frac{7\lambda}{2}$ .
$\lambda = \frac{d^2}{7D}$ . So the answer is (b).

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