In biprism experiment, 21 fringes are observed in a given region using light of wavelength 4800. If light of wavelength 5600 is used, the number of fringes in the same region will be (a) 18 (b) 24 (c) 14 (d) 21

Answer: (a). For a fixed region Nβ is constant and β ∝ λ, so Nλ = constant. N₂ = (21 × 4800)/(5600) = 18. So the answer is (a) 18.

In biprism experiment, 21 fringes are observed in a given region… | MHT CET 2021 (21 Sep, Shift 1)

Q21MHT CET 2021 · 21 SEP · SHIFT 1Easy

Biprism, Thin Films & Other Devices

In biprism experiment, 21 fringes are observed in a given region using light of wavelength 4800 $\text{\AA}$ . If light of wavelength 5600 $\text{\AA}$ is used, the number of fringes in the same region will be

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Answer: (a)

For a fixed region $N\beta$ is constant and $\beta \propto \lambda$ , so $N\lambda$ = constant.
$N_2 = \frac{21 \times 4800}{5600} = 18$ .
So the answer is (a) 18.

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