In biprism experiment, 6 th bright band with wavelength ' λ₁ ' coincides with 7 th dark band with wavelength ' λ₂ ' then the ratio λ₁: λ₂ is (other setting remains the same) (a) 7: 6 (b) 13: 12 (c) 12: 13 (d) 6: 7

Answer: (b). 6th bright: y = (6λ₁ D)/(d); 7th dark: y = (13λ₂ D)/(2d). Equate: 6λ₁ = 6.5λ₂. λ₁: λ₂ = 13: 12. So the answer is (b).

In biprism experiment, 6 th bright band with wavelength ' λ₁ '… | MHT CET 2021 (23 Sep, Shift 2)

Q22MHT CET 2021 · 23 SEP · SHIFT 2Medium

Biprism, Thin Films & Other Devices

In biprism experiment, $6$ th bright band with wavelength ' $\lambda_1$ ' coincides with $7$ th dark band with wavelength ' $\lambda_2$ ' then the ratio $\lambda_1 : \lambda_2$ is (other setting remains the same)

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Answer: (b)

6th bright: $y = \frac{6\lambda_1 D}{d}$ ; 7th dark: $y = \frac{13\lambda_2 D}{2d}$ .
Equate: $6\lambda_1 = 6.5\lambda_2$ .
$\lambda_1 : \lambda_2 = 13 : 12$ . So the answer is (b).

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