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JEE Main 2021 (27 Jul, Shift 1) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from JEE Main 2021 (27 Jul, Shift 1)

Q88JEE Main 2021 · 27 JUL · SHIFT 1Medium

Bohr Model: Orbits, Speed & Angular Momentum

In Bohr's atomic model, the electron is assumed to revolve in a circular orbit of radius 0.5 A˚\mathring{A}. If the speed of electron is 2.2 ×\times 106 m/s, then the current associated with the electron will be _____________ ×\times 10−-2 mA. [Take π\pi as 227\frac{22}{7} ]

Numerical answer type. Work it out, then open the answer.

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Answer: 112

  1. I=eT=ev2πrI = \frac{e}{T} = \frac{ev}{2\pi r}
  2. I=1.6×10−19×2.2×1062×227×0.5×10−10=3.52×10−133.143×10−10I = \frac{1.6\times10^{-19}\times2.2\times10^6}{2\times\frac{22}{7}\times0.5\times10^{-10}} = \frac{3.52\times10^{-13}}{3.143\times10^{-10}}
  3. I=1.12×10−3 A=1.12 mA=112×10−2 mAI = 1.12\times10^{-3}\text{ A} = 1.12\text{ mA} = 112\times10^{-2}\text{ mA}
  4. So the answer is 112.
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