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MHT CET 2019 (3 May, Shift 1) · Electric Charge & Coulomb's Law

Electric Charge & Coulomb's Law question from MHT CET 2019 (3 May, Shift 1)

Q63MHT CET 2019 · 3 MAY · SHIFT 1Easy

Electric Charge & Coulomb's Law

In case of dimensions of electric field and electric dipole moment the power of mass is respectively,

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Answer: (b)

  1. E=Fq=[MLT−2][AT]=[M1L1T−3A−1]E = \dfrac{F}{q} = \dfrac{[MLT^{-2}]}{[AT]} = [M^1L^1T^{-3}A^{-1}], power of mass =1= 1.
  2. p=q⋅2l=[A1T1L1]p = q\cdot 2l = [A^1T^1L^1], power of mass =0= 0.
  3. So the answer is (b) 1,01, 0.
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