In case of photoelectric effect, the graph of measured stopping potential (V₀) against frequency ' v ' of incident light is a straight line. The slope of this line multiplied by the charge of electron (e) gives (a) the work function of the metal. (b) the Planck's constant. (c) the maximum kinetic energy of the ejected electrons. (d) the threshold frequency for photoejection from the metal.

Answer: (b). V₀ = h/eν - φ/e, so slope = h/e. Slope × e = h. So the answer is (b) the Planck's constant.

In case of photoelectric effect, the graph of measured stopping… | MHT CET 2024 (11 May, Shift 2)

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Photoelectric Experiment: Intensity, Stopping Potential & Graphs

In case of photoelectric effect, the graph of measured stopping potential $(\mathrm{V}_0)$ against frequency ' $v$ ' of incident light is a straight line. The slope of this line multiplied by the charge of electron (e) gives

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Answer: (b)

$V_0 = \dfrac{h}{e}\nu - \dfrac{\phi}{e}$ , so slope $= h/e$ .
Slope $\times e = h$ .
So the answer is (b) the Planck's constant.

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Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from MHT CET 2024 (11 May, Shift 2)

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