In case of photoelectric emission from certain metal, the cutoff frequency is ν. If the radiation of frequency 3ν is incident on the metal plate, the maximum possible velocity of the emitted electrons will be ( m = mass of electron, h = Planck's constant) (a) √((hν)/(2m)) (b) √(hν/m) (c) 2(√(hν/m)) (d) √((2hν)/(m))

Answer: (c). 1/2mvmax² = h(3ν) - hν = 2hν vmax = √((4hν)/(m)) = 2√(hν/m) So the answer is (c) 2(√(hν/m)).

In case of photoelectric emission from certain metal, the cutoff… | MHT CET 2026 (18 Apr, Shift 1)

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Photoelectric Effect: Einstein's Equation

In case of photoelectric emission from certain metal, the cutoff frequency is $\nu$ . If the radiation of frequency $3\nu$ is incident on the metal plate, the maximum possible velocity of the emitted electrons will be ( $m$ = mass of electron, $h$ = Planck's constant)

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Answer: (c)

$\frac{1}{2}mv_{max}^2 = h(3\nu) - h\nu = 2h\nu$
$v_{max} = \sqrt{\frac{4h\nu}{m}} = 2\sqrt{\frac{h\nu}{m}}$
So the answer is (c) $2\left(\sqrt{\frac{h\nu}{m}}\right)$ .

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