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MHT CET 2021 (23 Sep, Shift 1) · Junction Transistor

Junction Transistor question from MHT CET 2021 (23 Sep, Shift 1)

Q71MHT CET 2021 · 23 SEP · SHIFT 1Medium

Junction Transistor

In common emitter amplifier, a change of 0.2 mA in the base current causes a change of 5 mA in the collector current. If input resistance is 2 kΩ\Omega and voltage gain is 75, the load resistance used in the circuit is

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Answer: (d)

  1. β=ΔICΔIB=50.2=25\beta = \dfrac{\Delta I_C}{\Delta I_B} = \dfrac{5}{0.2} = 25
  2. AV=βRLRi⇒75=25×RL2 kΩA_V = \beta \dfrac{R_L}{R_i} \Rightarrow 75 = 25 \times \dfrac{R_L}{2\text{ k}\Omega}
  3. RL=6R_L = 6 kΩ\Omega
  4. So the answer is (d) 6 kΩ\Omega.
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