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MHT CET 2026 (15 Apr, Shift 2) · Junction Transistor

Junction Transistor question from MHT CET 2026 (15 Apr, Shift 2)

Q16MHT CET 2026 · 15 APR · SHIFT 2Medium

Junction Transistor

In common emitter amplifier, a change of $0.2$ mA in the base current causes a change of $5$ mA in the collector current. If input resistance is $2$ k $\Omega$ and voltage gain is $75$ , the load resistance used in the circuit is

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Answer: (d)

$\beta = \dfrac{\Delta I_C}{\Delta I_B} = \dfrac{5}{0.2} = 25$
$A_V = \beta \dfrac{R_L}{R_i} \Rightarrow 75 = 25 \times \dfrac{R_L}{2\text{ k}\Omega}$
$R_L = 6$ k $\Omega$
So the answer is (d) $6$ k $\Omega$ .

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