In common emitter amplifier, using output resistance 5000 Ω and input resistance 2000 Ω, if the peak value of input signal voltage is 10 mV and β = 50, then peak value of output voltage is (a) 5 × 10⁻⁶ V (b) 12.50 × 10⁻⁶ V (c) 1.25 V (d) 125.0 V

Answer: (c). AV = β(Ro)/(Ri) = 50 × (5000)/(2000) = 125 Vo = AV Vi = 125 × 10 mV = 1250 mV So the answer is (c) 1.25 V.

In common emitter amplifier, using output resistance 5000 Ω and input… | MHT CET 2026 (13 May, Shift 1)

Q8MHT CET 2026 · 13 MAY · SHIFT 1Easy

Junction Transistor

In common emitter amplifier, using output resistance $5000\,\Omega$ and input resistance $2000\,\Omega$ , if the peak value of input signal voltage is $10$ mV and $\beta = 50$ , then peak value of output voltage is

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Answer: (c)

$A_V = \beta\frac{R_o}{R_i} = 50 \times \frac{5000}{2000} = 125$
$V_o = A_V V_i = 125 \times 10\text{ mV} = 1250$ mV
So the answer is (c) $1.25$ V.

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