In common emitter mode of a transistor, the current gain is 8. The input impedance is 25 kΩ and load resistance is 75 kΩ. The power gain is (a) 192 (b) 112 (c) 316 (d) 224

Answer: (a). AP = β²(RL)/(Ri) AP = 8² × 75/25 = 64 × 3 = 192 So the answer is (a) 192.

In common emitter mode of a transistor, the current gain is 8. The… | MHT CET 2025 (21 Apr, Shift 2)

Q25MHT CET 2025 · 21 APR · SHIFT 2Easy

Junction Transistor

In common emitter mode of a transistor, the current gain is 8. The input impedance is $25\text{ k}\Omega$ and load resistance is $75\text{ k}\Omega$ . The power gain is

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Answer: (a)

$A_P = \beta^2\frac{R_L}{R_i}$
$A_P = 8^2 \times \frac{75}{25} = 64 \times 3 = 192$
So the answer is (a) 192.

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