In common emitter transistor amplifier, load resistance is 6.5 kΩ and an input resistance is 1.3 kΩ. If the current gain is 78, the voltage gain is (a) 780 (b) 390 (c) 260 (d) 50

Answer: (b). AV = β(RL)/(Ri) AV = 78 × (6.5)/(1.3) = 78 × 5 = 390 So the answer is (b) 390.

In common emitter transistor amplifier, load resistance is 6.5 kΩ and… | MHT CET 2024 (3 May, Shift 1)

Q37MHT CET 2024 · 3 MAY · SHIFT 1Easy

Junction Transistor

In common emitter transistor amplifier, load resistance is $6.5\text{ k}\Omega$ and an input resistance is $1.3\text{ k}\Omega$ . If the current gain is 78, the voltage gain is

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Answer: (b)

$A_V = \beta\frac{R_L}{R_i}$
$A_V = 78 \times \frac{6.5}{1.3} = 78 \times 5 = 390$
So the answer is (b) 390.

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