In connection with the circuit drawn below, the value of current flowing through 2 k Ω resistor is _________ × 10 - 4 A. Numerical answer type. Work it out, then open the answer.

Answer: 25. Without the Zener, the voltage across 2 kΩ would be 10 × 2/3 = 6.67 V, which is above 5 V, so the Zener breaks down. The Zener holds the voltage across the 2 kΩ resistor at 5 V. I = 5/2000 = 2.5 × 10⁻³ A = 25 × 10⁻⁴ A. So the answer is 25.

In connection with the circuit drawn below, the value of current… | JEE Main 2021 (24 Feb, Shift 1)

Q78JEE Main 2021 · 24 FEB · SHIFT 1Medium

P-N Junction Diode

In connection with the circuit drawn below, the value of current flowing through 2 k $\Omega$ resistor is _________ $\times$ 10 $-$ 4 A.

Numerical answer type. Work it out, then open the answer.

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Answer: 25

Without the Zener, the voltage across $2\ k\Omega$ would be $10 \times \frac{2}{3} = 6.67$ V, which is above $5$ V, so the Zener breaks down.
The Zener holds the voltage across the $2\ k\Omega$ resistor at $5$ V.
$I = \frac{5}{2000} = 2.5 \times 10^{-3}$ A $= 25 \times 10^{-4}$ A.
So the answer is 25.

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