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MHT CET 2026 (13 May, Shift 2) · Diffraction at a Single Slit

Diffraction at a Single Slit question from MHT CET 2026 (13 May, Shift 2)

Q14MHT CET 2026 · 13 MAY · SHIFT 2Medium

Diffraction at a Single Slit

In double slit experiment, the two slits are $1$ mm apart and the screen is placed $1$ m away. A monochromatic light of wavelength $500$ nm is used. What will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single slit pattern?

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Answer: (a)

Width of single-slit central maximum $= \dfrac{2\lambda D}{a}$ ; double-slit fringe width $\beta = \dfrac{\lambda D}{d}$
Ten maxima inside: $\dfrac{2\lambda D}{a} = 10\,\dfrac{\lambda D}{d} \Rightarrow a = \dfrac{2d}{10}$
$a = \dfrac{2 \times 1}{10} = 0.2$ mm. So the answer is (a).

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