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JEE Main 2022 (25 Jul, Shift 1) · Spring Systems

Spring Systems question from JEE Main 2022 (25 Jul, Shift 1)

Q59JEE Main 2022 · 25 JUL · SHIFT 1Medium

Spring Systems

Figure

In figure (A)(A), mass '2m2m' is fixed on mass 'mm ' which is attached to two springs of spring constant kk. In figure (B), mass 'mm' is attached to two springs of spring constant 'kk' and '2k2k. If mass 'mm' in (A) and in (B) are displaced by distance 'xx horizontally and then released, then time period T1T_1 and T2T_2 corresponding to (A)(A) and (B) respectively follow the relation.

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Answer: (a)

  1. (A) mass 3m3m, both springs act: k=2kk = 2k, so T1=2π3m2kT_1 = 2\pi\sqrt{\frac{3m}{2k}}.
  2. (B) mass mm, keff=k+2k=3kk_{eff} = k + 2k = 3k, so T2=2πm3kT_2 = 2\pi\sqrt{\frac{m}{3k}}.
  3. T1T2=3m2k⋅3km=92=32\frac{T_1}{T_2} = \sqrt{\frac{3m}{2k}\cdot\frac{3k}{m}} = \sqrt{\frac{9}{2}} = \frac{3}{\sqrt{2}}
  4. So the answer is (a).
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