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JEE Main 2024 (6 Apr, Shift 2) · Other / Mixed: Atoms & Bohr Links

Other / Mixed: Atoms & Bohr Links question from JEE Main 2024 (6 Apr, Shift 2)

Q2JEE Main 2024 · 6 APR · SHIFT 2Medium

Other / Mixed: Atoms & Bohr Links

In Franck-Hertz experiment, the first dip in the current-voltage graph for hydrogen is observed at $10.2\text{ V}$ . The wavelength of light emitted by hydrogen atom when excited to the first excitation level is ________ nm. (Given hc $= 1245\text{ eV nm},\ e = 1.6 \times 10^{-19}\text{ C}$ ).

Numerical answer type. Work it out, then open the answer.

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Answer: 122

First dip at 10.2 V means the n = 1 to n = 2 excitation needs 10.2 eV.
On returning, the atom emits a photon of 10.2 eV: $\lambda = \frac{hc}{E}$
$\lambda = \frac{1245}{10.2} \approx 122\text{ nm}$

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