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MHT CET 2026 (13 Apr, Shift 1) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from MHT CET 2026 (13 Apr, Shift 1)

Q9MHT CET 2026 · 13 APR · SHIFT 1Medium

Organ Pipes & Resonance Tube

In fundamental mode, the time required for the sound wave to reach upto the closed end of a pipe filled with air is $t$ second. The frequency of vibration of air column is

( $\lambda$ = wavelength of the wave)

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Answer: (b)

Fundamental of closed pipe: $L = \frac{\lambda}{4}$ and $f = \frac{v}{4L}$ .
Time to travel the pipe length: $t = \frac{L}{v}$ .
$f = \frac{1}{4}\cdot\frac{v}{L} = \frac{1}{4t} = \frac{0.25}{t}$
So the answer is (b) $\frac{0.25}{t}$ .

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