In hydrogen atom an electron revolves around a proton (in nucleus) at a distance 'r' m. the intensity of electric field due to the proton at distance 'r' is 5 × 10¹¹ NC⁻¹, the magnitude of force between the electron and proton is [charge on electron = 1.6 × 10⁻¹⁹ C ] (a) 4 × 10⁸ N (b) 8 × 10⁸ N (c) 4 × 10⁻⁸ N (d) 8 × 10⁻⁸ N

Answer: (d). Force on the electron in the proton's field: F = eE. F = 1.6 × 10⁻¹⁹ × 5 × 10¹¹ = 8 × 10⁻⁸ N So the answer is (d) 8 × 10⁻⁸ N.

In hydrogen atom an electron revolves around a proton (in nucleus) at… | MHT CET 2021 (23 Sep, Shift 1)

Q28MHT CET 2021 · 23 SEP · SHIFT 1Easy

Electric Field & Field Lines

In hydrogen atom an electron revolves around a proton (in nucleus) at a distance 'r' m. the intensity of electric field due to the proton at distance 'r' is $5 \times 10^{11}\text{ NC}^{-1}$ , the magnitude of force between the electron and proton is [charge on electron $= 1.6 \times 10^{-19}\text{ C}$ ]

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Answer: (d)

Force on the electron in the proton's field: $F = eE$ .
$F = 1.6 \times 10^{-19} \times 5 \times 10^{11} = 8 \times 10^{-8}\text{ N}$
So the answer is (d) $8 \times 10^{-8}\text{ N}$ .

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Electric Field & Field Lines question from MHT CET 2021 (23 Sep, Shift 1)

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