In hydrogen atom spectrum, ( R → Rydberg's constant) A. the maximum… | JEE Main 2026 (23 Jan, Shift 1)

Q5JEE Main 2026 · 23 JAN · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series

In hydrogen atom spectrum, ( $R \rightarrow$ Rydberg's constant)

A. the maximum wavelength of the radiation of Lyman series is $\frac{4}{3R}$

B. the Balmer series lies in the visible region of the spectrum

C. the minimum wavelength of the radiation of Paschen series is $\frac{9}{R}$

D. the minimum wavelength of Lyman series is $\frac{5}{4R}$

Choose the correct answer from the options given below:

Show answer and solution

Answer: (d)

A: Lyman maximum $\lambda$ ( $2 \to 1$ ): $\frac{1}{\lambda} = \frac{3R}{4} \Rightarrow \lambda = \frac{4}{3R}$ . Correct.
B: Balmer lines ( $365$ to $656$ nm) are visible. Correct.
C: Paschen minimum $\lambda$ (limit): $\lambda = \frac{9}{R}$ . Correct.
D: Lyman minimum $\lambda$ (limit) is $\frac{1}{R}$ , not $\frac{5}{4R}$ . Wrong.
So the answer is (d) A, B and C Only.

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