In hydrogen spectrum, the shortest wavelength in the Balmer series is λ. The shortest wavelength in the Brackett series is: (a) 4λ (b) 9λ (c) 16λ (d) 2λ

Answer: (a). Shortest wavelength of a series: λ = (n₁²)/(R) Balmer ( n₁=2): λ = 4/R; Brackett ( n₁=4): λ' = 16/R λ' = 4λ So the answer is (a) 4λ.

In hydrogen spectrum, the shortest wavelength in the Balmer series is… | NEET 2023

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Hydrogen Spectrum & Spectral Series

In hydrogen spectrum, the shortest wavelength in the Balmer series is $\lambda$ . The shortest wavelength in the Brackett series is:

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Answer: (a)

Shortest wavelength of a series: $\lambda = \frac{n_1^2}{R}$
Balmer ( $n_1=2$ ): $\lambda = \frac{4}{R}$ ; Brackett ( $n_1=4$ ): $\lambda' = \frac{16}{R}$
$\lambda' = 4\lambda$
So the answer is (a) $4\lambda$ .

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