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MHT CET 2026 (14 May, Shift 2) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from MHT CET 2026 (14 May, Shift 2)

Q19MHT CET 2026 · 14 MAY · SHIFT 2Medium

Bohr Model: Orbits, Speed & Angular Momentum

In hydrogenth atom, an electron jumps from higher orbit to lower orbit so that radius of the lower orbit is (14)\left(\frac{1}{4}\right) of radius of higher orbit. If speed of electron in higher orbit was V, then speed in lower orbit is

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Answer: (d)

  1. r∝n2r \propto n^2: rr becomes 14\frac{1}{4}, so nn becomes half.
  2. v∝1nv \propto \frac{1}{n}, so vv doubles.
  3. So the answer is (d) 2V2V.
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