In LCR series circuit, an alternating e.m.f. 'e' and current ' i ' are given by equations e = 160sin (100t) Volt and i = 250sin (100t + π/3) mA. The average power dissipated in the circuit is (a) 2.5 W (b) 4.0 W (c) 10 W (d) 100 W

Answer: (c). P = (e₀i₀)/(2)cos φ with φ = 60° P = (160×0.25)/(2)×0.5 P = 10 W So the answer is (c) 10 W.

In LCR series circuit, an alternating e.m.f. 'e' and current ' i '… | MHT CET 2024 (16 May, Shift 1)

Q29MHT CET 2024 · 16 MAY · SHIFT 1Easy

Power, Power Factor & Wattless Current

In LCR series circuit, an alternating e.m.f. 'e' and current ' $i$ ' are given by equations $e = 160\sin(100t)$ Volt and $i = 250\sin\left(100t + \frac{\pi}{3}\right)\text{ mA}$ . The average power dissipated in the circuit is

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Answer: (c)

$P = \frac{e_0i_0}{2}\cos\phi$ with $\phi = 60^\circ$
$P = \frac{160\times0.25}{2}\times0.5$
$P = 10\text{ W}$
So the answer is (c) 10 W.

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Power, Power Factor & Wattless Current question from MHT CET 2024 (16 May, Shift 1)

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