In LCR series circuit at resonance (a) the current is minimum. (b) the impedance is maximum. (c) the current leads the voltage by π/2 (d) the current and voltage are in phase.

Answer: (d). At resonance XL = XC, so Z = R (minimum) and current is maximum. tan φ = (XL - XC)/(R) = 0 ⇒ φ = 0 So the answer is (d) the current and voltage are in phase.

In LCR series circuit at resonance | MHT CET 2026 (17 Apr, Shift 1)

Q10MHT CET 2026 · 17 APR · SHIFT 1Easy

Resonance, Bandwidth & Q Factor

In LCR series circuit at resonance

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Answer: (d)

At resonance $X_L = X_C$ , so $Z = R$ (minimum) and current is maximum.
$\tan\phi = \dfrac{X_L - X_C}{R} = 0 \Rightarrow \phi = 0$
So the answer is (d) the current and voltage are in phase.

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