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JEE Main 2019 (10 Apr, Shift 2) · Transitions, Photon Emission & Excitation

Transitions, Photon Emission & Excitation question from JEE Main 2019 (10 Apr, Shift 2)

Q58JEE Main 2019 · 10 APR · SHIFT 2Difficult

Transitions, Photon Emission & Excitation

In Li+ +, electron in first Bohr orbit is excited to a level by a radiation of wavelength λ\lambda. When the ion gets deexcited to the ground state in all possible ways (including intermediate emissions), a total of six spectral lines are observed. What is the value of λ\lambda?

(Given: H = 6.63 × 10–34 Js; c = 3 × 108 ms –1)

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Answer: (a)

  1. Six lines: n(n−1)2=6⇒\frac{n(n-1)}{2} = 6 \Rightarrow excited to n=4n = 4.
  2. For Li++^{++} (Z=3Z = 3): E=13.6×9×(1−116)=114.75E = 13.6 \times 9 \times \left(1 - \frac{1}{16}\right) = 114.75 eV
  3. λ=hcE=6.63×10−34×3×108114.75×1.6×10−19=1.08×10−8\lambda = \frac{hc}{E} = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{114.75 \times 1.6 \times 10^{-19}} = 1.08 \times 10^{-8} m
  4. So the answer is (a) 10.8 nm.
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