In metre-bridge the balancing length from left is found to be 20 cm when standard resistance of 1 Ω is in right gap. The value of unknown resistance is (a) 0.25 Ω (b) 0.4 Ω (c) 0.5 Ω (d) 4 Ω

Answer: (a). X/1 = (l)/(100 - l) = 20/80 X = 0.25 Ω So the answer is (a) 0.25 Ω.

In metre-bridge the balancing length from left is found to be 20 cm… | NEET 1999 (AIPMT)

Q87NEET 1999 · AIPMTEasy

Wheatstone Bridge & Metre Bridge

In metre-bridge the balancing length from left is found to be $20\text{ cm}$ when standard resistance of $1\ \Omega$ is in right gap. The value of unknown resistance is

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Answer: (a)

$\frac{X}{1} = \frac{l}{100 - l} = \frac{20}{80}$
$X = 0.25\ \Omega$
So the answer is (a) $0.25\ \Omega$ .

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Wheatstone Bridge & Metre Bridge question from NEET 1999 (AIPMT)

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