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MHT CET 2021 (22 Sep, Shift 2) · Energy of the Electron & Energy Levels

Energy of the Electron & Energy Levels question from MHT CET 2021 (22 Sep, Shift 2)

Q32MHT CET 2021 · 22 SEP · SHIFT 2Easy

Energy of the Electron & Energy Levels

In $n$ th Bohr orbit, the ratio of the kinetic energy of an electron to the total energy of it, is

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Answer: (b)

In a Bohr orbit $KE = \frac{ke^2}{2r}$ and $TE = -\frac{ke^2}{2r}$ , so $KE = -TE$ .
$\frac{KE}{TE} = -1$
So the answer is (b) $1 : -1$ .

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