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NEET 1999 (AIPMT) · Radioactive Decays: Alpha, Beta, Gamma

Radioactive Decays: Alpha, Beta, Gamma question from NEET 1999 (AIPMT)

Q42NEET 1999 · AIPMTEasy

Radioactive Decays: Alpha, Beta, Gamma

In one $\alpha$ and $2\beta$ -emissions

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Answer: (d)

One $\alpha$ : $\Delta A = -4$ , $\Delta Z = -2$ .
Two $\beta^-$ : $\Delta A = 0$ , $\Delta Z = +2$ .
Net: $\Delta A = -4$ , $\Delta Z = 0$ .
So the answer is (d) atomic number remains unchanged.

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