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NEET 1999 (AIPMT) · Radioactive Decays: Alpha, Beta, Gamma

Radioactive Decays: Alpha, Beta, Gamma question from NEET 1999 (AIPMT)

Q42NEET 1999 · AIPMTEasy

Radioactive Decays: Alpha, Beta, Gamma

In one α\alpha and 2β2\beta-emissions

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Answer: (d)

  1. One α\alpha: ΔA=−4\Delta A = -4, ΔZ=−2\Delta Z = -2.
  2. Two β−\beta^-: ΔA=0\Delta A = 0, ΔZ=+2\Delta Z = +2.
  3. Net: ΔA=−4\Delta A = -4, ΔZ=0\Delta Z = 0.
  4. So the answer is (d) atomic number remains unchanged.
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