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MHT CET 2026 (12 May, Shift 1) · P-N Junction Diode

P-N Junction Diode question from MHT CET 2026 (12 May, Shift 1)

Q13MHT CET 2026 · 12 MAY · SHIFT 1Medium

P-N Junction Diode

In one branch, 40 Ω40\ \Omega resistance and a p-n junction diode are connected in series and in another branch, 40 Ω40\ \Omega resistance is connected. Both the branches are connected in parallel to each other. The total resistance of the circuit when a) diode is forward biased and when b) diode is reverse biased respectively are {consider the p-n junction diode as an ideal diode}

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Answer: (c)

  1. Forward biased ideal diode acts as a short: both 40 Ω40\ \Omega branches in parallel, R=40×4080=20 ΩR = \dfrac{40\times 40}{80} = 20\ \Omega.
  2. Reverse biased ideal diode acts as an open switch: only one 40 Ω40\ \Omega branch, R=40 ΩR = 40\ \Omega.
  3. So the answer is (c) 20 Ω20\ \Omega and 40 Ω40\ \Omega.
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