In P th second, a particle describes angular displacement of ' β ' rad. If it starts from rest, the angular acceleration is (a) (β)/(P) (b) (β)/((P-1)) (c) (2β)/((2P-1)) (d) ((2β+1))/((2P-1))

Answer: (c). Displacement in the n th second from rest: θn = (α)/(2)(2n-1). β = (α)/(2)(2P-1) So the answer is (c) α = (2β)/(2P-1).

In P th second, a particle describes angular displacement of ' β '… | MHT CET 2023 (12 May, Shift 2)

Q27MHT CET 2023 · 12 MAY · SHIFT 2Medium

Rotational Kinematics & Dynamics

In $P$ th second, a particle describes angular displacement of ' $\beta$ ' rad. If it starts from rest, the angular acceleration is

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Answer: (c)

Displacement in the $n$ th second from rest: $\theta_n = \frac{\alpha}{2}(2n-1)$ .
$\beta = \frac{\alpha}{2}(2P-1)$
So the answer is (c) $\alpha = \frac{2\beta}{2P-1}$ .

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