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MHT CET 2021 (22 Sep, Shift 2) · Energy Stored & Force between Plates

Energy Stored & Force between Plates question from MHT CET 2021 (22 Sep, Shift 2)

Q25MHT CET 2021 · 22 SEP · SHIFT 2Easy

Energy Stored & Force between Plates

In parallel plate capacitor, electric field between the plates is 'EE'. If the charge on the plates is 'QQ' then the force on each plate is

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Answer: (d)

  1. Field due to one plate =σ2ε0=E2= \frac{\sigma}{2\varepsilon_0} = \frac{E}{2}.
  2. Force on the other plate: F=Q⋅E2F = Q \cdot \frac{E}{2}
  3. So the answer is (d) QE2\frac{QE}{2}.
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