In photoelectric effect, the stopping potential (V₀) v/s frequency (v) curve is plotted. ( h is the Planck's constant and φ₀ is work function of metal) (A) V₀ v/s v is linear. (B) The slope of V₀ v/s v curve = (φ₀)/(h) (C) h constant is related to the slope of V₀ v/s v line. (D) The value of electric charge of electron is not required to determine h using the V₀ v/s v curve. (E) The work function can be estimated without knowing the value of h. Choose the correct answer from the options given below: (a) (A), (C) and (E) only (b) (C) and (D) only (c) (A), (B) and (C) only (d) (D) and (E) only

Answer: (a). V₀ = h/eν - (φ₀)/(e). (A) True: V₀ is linear in ν. (B) False: slope is h/e, not φ₀/h. (C) True: slope = h/e. (D) False: h = e × slope, so e is needed. (E) True: the V₀ -axis intercept is -φ₀/e, giving φ₀ in eV directly without h. So the answer is (a) (A), (C) and (E) only.

In photoelectric effect, the stopping potential (V₀) v/s frequency… | JEE Main 2025 (24 Jan, Shift 2)

Q16JEE Main 2025 · 24 JAN · SHIFT 2Easy

Photoelectric Experiment: Intensity, Stopping Potential & Graphs

In photoelectric effect, the stopping potential $(\mathrm{V}_0)\text{ v/s}$ frequency $(v)$ curve is plotted. ( h is the Planck's constant and $\phi_0$ is work function of metal)

(A) $\mathrm{V}_0\text{ v/s } v$ is linear.

(B) The slope of $\mathrm{V}_0\text{ v/s } v$ curve $= \frac{\phi_0}{\mathrm{h}}$

(D) The value of electric charge of electron is not required to determine h using the $\mathrm{V}_0\text{ v/s } v$ curve. (E) The work function can be estimated without knowing the value of $h$ .

Choose the correct answer from the options given below:

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Answer: (a)

$V_0 = \frac{h}{e}\nu - \frac{\phi_0}{e}$ .
(A) True: $V_0$ is linear in $\nu$ . (B) False: slope is $h/e$ , not $\phi_0/h$ . (C) True: slope $= h/e$ .
(D) False: $h = e \times \text{slope}$ , so $e$ is needed.
(E) True: the $V_0$ -axis intercept is $-\phi_0/e$ , giving $\phi_0$ in eV directly without $h$ .
So the answer is (a) (A), (C) and (E) only.

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Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from JEE Main 2025 (24 Jan, Shift 2)

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