In potentiometer experiment, cells of e.m.f. ' E₁ ' and ' E₂ ' are connected in series (E₁ > E₂) the balancing length is 64 cm of the wire. If the polarity of E₂ is reversed, the balancing length becomes 32 cm. The ratio (E₁)/(E₂) is (a) 1: 1 (b) 6: 1 (c) 3: 1 (d) 2: 1

Answer: (c). Series aiding: E₁+E₂ = k(64); series opposing: E₁-E₂ = k(32). (E₁+E₂)/(E₁-E₂) = 2 ⇒ E₁ = 3E₂ So the answer is (c) 3:1.

In potentiometer experiment, cells of e.m.f. ' E₁ ' and ' E₂ ' are… | MHT CET 2021 (23 Sep, Shift 1)

Q56MHT CET 2021 · 23 SEP · SHIFT 1Medium

Potentiometer

In potentiometer experiment, cells of e.m.f. ' $E_1$ ' and ' $E_2$ ' are connected in series $(E_1 > E_2)$ the balancing length is $64\text{ cm}$ of the wire. If the polarity of $E_2$ is reversed, the balancing length becomes $32\text{ cm}$ . The ratio $\frac{E_1}{E_2}$ is

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Answer: (c)

Series aiding: $E_1+E_2 = k(64)$ ; series opposing: $E_1-E_2 = k(32)$ .
$\dfrac{E_1+E_2}{E_1-E_2} = 2 \Rightarrow E_1 = 3E_2$
So the answer is (c) $3:1$ .

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Potentiometer question from MHT CET 2021 (23 Sep, Shift 1)

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