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MHT CET 2024 (10 May, Shift 1) · Potentiometer

Potentiometer question from MHT CET 2024 (10 May, Shift 1)

Q33MHT CET 2024 · 10 MAY · SHIFT 1Medium

Potentiometer

In potentiometer experiment, cells of e.m.f. $E_1$ and $E_2$ are connected in series $(E_1 > E_2)$ the balancing length is 80 cm of the wire. If the polarity of $E_2$ is reversed, the balancing length becomes 20 cm. The ratio $E_1/E_2$ is

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Answer: (d)

$\frac{E_1 + E_2}{E_1 - E_2} = \frac{80}{20} = 4$ .
$E_1 + E_2 = 4E_1 - 4E_2 \Rightarrow 3E_1 = 5E_2$ .
So the answer is (d) $5:3$ .

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