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MHT CET 2023 (14 May, Shift 2) · Potentiometer

Potentiometer question from MHT CET 2023 (14 May, Shift 2)

Q40MHT CET 2023 · 14 MAY · SHIFT 2Medium

Potentiometer

In potentiometer experiment, the balancing length is $8\text{ m}$ when two cells $E_1$ and $E_2$ are joined in series. When two cells are connected in opposition the balancing length is $4\text{ m}$ . The ratio of the e.m.f. of the two cells $\left(\frac{E_1}{E_2}\right)$ is

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Answer: (d)

$\frac{E_1 + E_2}{E_1 - E_2} = \frac{8}{4} = 2$ .
$E_1 + E_2 = 2E_1 - 2E_2 \Rightarrow E_1 = 3E_2$ .
So the answer is (d) $3:1$ .

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