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JEE Main 2024 (1 Feb, Shift 1) · Resonance, Bandwidth & Q Factor

Resonance, Bandwidth & Q Factor question from JEE Main 2024 (1 Feb, Shift 1)

Q39JEE Main 2024 · 1 FEB · SHIFT 1Easy

Resonance, Bandwidth & Q Factor

In series LCR circuit, the capacitance is changed from CC to 4C4C. To keep the resonance frequency unchanged, the new inductance should be:

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Answer: (c)

  1. f0=12πLCf_0 = \dfrac{1}{2\pi\sqrt{LC}} stays the same if LCLC stays the same.
  2. L′(4C)=LC⇒L′=L4L'(4C) = LC \Rightarrow L' = \dfrac{L}{4}
  3. Change =L−L4=34L= L - \dfrac{L}{4} = \dfrac{3}{4}L (a reduction).
  4. So the answer is (c) reduced by 34L\frac{3}{4}L.
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