In series LCR resonant circuit, R = 800 Ω, C = 2 and voltage across resistance is 200 V. The angular frequency is 250 rad/s. At resonance, the voltage across the inductance is (a) 400 V (b) 250 V (c) 1000 V (d) 500 V

Answer: (d). I = VR/R = (200)/(800) = 0.25 A At resonance XL = XC = (1)/(ω C) = 1250×2×10⁻⁶ = 2000 Ω VL = IXL = 0.25×2000 = 500 V So the answer is (d) 500 V.

In series LCR resonant circuit, R = 800 Ω, C = 2 and voltage across… | MHT CET 2025 (21 Apr, Shift 1)

Q34MHT CET 2025 · 21 APR · SHIFT 1Medium

Resonance, Bandwidth & Q Factor

In series LCR resonant circuit, R $= 800\ \Omega,\ C = 2\ \mu\text{F}$ and voltage across resistance is 200 V. The angular frequency is $250\text{ rad/s}$ . At resonance, the voltage across the inductance is

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Answer: (d)

$I = \frac{V_R}{R} = \frac{200}{800} = 0.25$ A
At resonance $X_L = X_C = \frac{1}{\omega C} = \frac{1}{250\times2\times10^{-6}} = 2000\ \Omega$
$V_L = IX_L = 0.25\times2000 = 500$ V
So the answer is (d) 500 V.

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Resonance, Bandwidth & Q Factor question from MHT CET 2025 (21 Apr, Shift 1)

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