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MHT CET 2026 (13 Apr, Shift 1) · Resonance, Bandwidth & Q Factor

Resonance, Bandwidth & Q Factor question from MHT CET 2026 (13 Apr, Shift 1)

Q23MHT CET 2026 · 13 APR · SHIFT 1Medium

Resonance, Bandwidth & Q Factor

In series LCR resonant circuit, R=800 $\Omega$ , C = 2 $\mu$ F and voltage across resistance is 200 V. The angular frequency is 250 rad/s. At resonance the voltage across the capacitance is

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Answer: (b)

$I = \frac{V_R}{R} = \frac{200}{800} = 0.25$ A
$V_C = \frac{I}{\omega C} = \frac{0.25}{250\times2\times10^{-6}} = \frac{0.25}{5\times10^{-4}}$
$V_C = 500$ V
So the answer is (b) 500 V.

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