Physics Circle home Student Login

Home›Chapters›Units, Dimensions and Measurement PYQs›Units & Dimensions›Question 75

JEE Main 2019 (8 Apr, Shift 1) · Units & Dimensions

Units & Dimensions question from JEE Main 2019 (8 Apr, Shift 1)

Q75JEE Main 2019 · 8 APR · SHIFT 1Easy

Units & Dimensions

In SI units, the dimensions of ϵ0μ0\sqrt{\frac{\epsilon_0}{\mu_0}} is:

Show answer and solution

Answer: (b)

  1. [ε0]=[M−1L−3T4A2][\varepsilon_0] = [\mathrm{M^{-1}L^{-3}T^{4}A^{2}}], [μ0]=[MLT−2A−2][\mu_0] = [\mathrm{MLT^{-2}A^{-2}}]
  2. ε0μ0=[M−2L−4T6A4]\frac{\varepsilon_0}{\mu_0} = [\mathrm{M^{-2}L^{-4}T^{6}A^{4}}]
  3. ε0μ0=[M−1L−2T3A2]\sqrt{\frac{\varepsilon_0}{\mu_0}} = [\mathrm{M^{-1}L^{-2}T^{3}A^{2}}] (inverse of resistance)
  4. So the answer is (b) A2T3M−1L−2\mathrm{A^2T^3M^{-1}L^{-2}}.
Report a mistake

More questions on Units & Dimensions