In the case of NAND gate, if A and B are the inputs and Y is the output then (a) Y = A · B (b) Y = A - B (c) Y = A + B (d) Y = A · B

Answer: (d). NAND = AND followed by NOT. Y = A · B. So the answer is (d).

In the case of NAND gate, if A and B are the inputs and Y is the… | MHT CET 2023 (11 May, Shift 1)

Q85MHT CET 2023 · 11 MAY · SHIFT 1Easy

Logic Gates

In the case of NAND gate, if A and B are the inputs and $\mathrm{Y}$ is the output then

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Answer: (d)

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