In the circuit diagram shown in figure given below, the current flowing through resistance 3 Ω is x/3 A. The value of x is ___________ Numerical answer type. Work it out, then open the answer.

Answer: 1. The 4 V and 8 V cells have their + terminals facing each other, so they oppose: net emf = 8 - 4 = 4 V. 3 ∥ 6 = 2 Ω; total R = 4.5 + 2 + 0.5 + 1 = 8 Ω I = 4/8 = 0.5 A I₃ = 0.5 × (6)/(3 + 6) = 1/3 A So x = 1.

In the circuit diagram shown in figure given below, the current… | JEE Main 2023 (11 Apr, Shift 1)

Q89JEE Main 2023 · 11 APR · SHIFT 1Medium

Kirchhoff's Laws & Measuring Instruments

In the circuit diagram shown in figure given below, the current flowing through resistance $3\ \Omega$ is $\frac{x}{3}\text{ A}$ . The value of $x$ is ___________

Numerical answer type. Work it out, then open the answer.

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Answer: 1

The 4 V and 8 V cells have their + terminals facing each other, so they oppose: net emf $= 8 - 4 = 4\text{ V}$ .
$3 \parallel 6 = 2\ \Omega$ ; total $R = 4.5 + 2 + 0.5 + 1 = 8\ \Omega$
$I = \frac{4}{8} = 0.5\text{ A}$
$I_3 = 0.5 \times \frac{6}{3 + 6} = \frac{1}{3}\text{ A}$
So $x = 1$ .

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