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JEE Main 2020 (5 Sep, Shift 2) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from JEE Main 2020 (5 Sep, Shift 2)

Q144JEE Main 2020 · 5 SEP · SHIFT 2Medium

Kirchhoff's Laws & Measuring Instruments

In the circuit, given in the figure currents in different branches and value of one resistor are shown. Then potential at point B with respect to the point A is:

Figure

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Answer: (c)

  1. Take VA=0V_A = 0. Crossing the 1 V cell from − to + towards C: VC=1 VV_C = 1\text{ V}.
  2. At D: 2 A arrives from B, 1 A leaves towards E, so 1 A flows D to C through 2 Ω2\ \Omega: VD=1+2=3 VV_D = 1 + 2 = 3\text{ V}.
  3. Crossing the 2 V cell from + (D side) to − (B side): VB=3−2=1 VV_B = 3 - 2 = 1\text{ V}
  4. So the answer is (c) +1 V.
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