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NEET 2024 · Pure R, L and C Circuits

Pure R, L and C Circuits question from NEET 2024

Q31NEET 2024Medium

Pure R, L and C Circuits

In the circuit shown below, the inductance LL is connected to an ac source. The current flowing in the circuit is I=I0sin⁡ωtI = I_0 \sin \omega t. The voltage drop (VL)(V_L) across LL is

Figure

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Answer: (d)

  1. VL=LdIdt=Lddt(I0sin⁡ωt)V_L = L\frac{dI}{dt} = L\frac{d}{dt}(I_0 \sin \omega t)
  2. VL=ωLI0cos⁡ωtV_L = \omega L I_0 \cos \omega t (voltage leads current by 90∘90^\circ)
  3. So the answer is (d) ωLI0cos⁡ωt\omega L I_0 \cos \omega t.
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