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JEE Main 2019 (12 Jan, Shift 2) · Combination of Capacitors

Combination of Capacitors question from JEE Main 2019 (12 Jan, Shift 2)

Q79JEE Main 2019 · 12 JAN · SHIFT 2Medium

Combination of Capacitors

In the circuit shown, find C if the effective capacitance of the whole circuit is to be 0.5 μ\muF. All values in the circuit are in μ\muF.

Figure

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Answer: (b)

  1. Left branch: two 22 in parallel =4= 4, in series with 22: 43\frac{4}{3}.
  2. Right branch: 22 and 22 in series =1= 1, in parallel with 11: 22; in series with the top 22: 11.
  3. Below C: 43+1=73\frac{4}{3} + 1 = \frac{7}{3}.
  4. 1C+37=10.5=2⇒1C=117⇒C=711 μF\frac{1}{C} + \frac{3}{7} = \frac{1}{0.5} = 2 \Rightarrow \frac{1}{C} = \frac{11}{7} \Rightarrow C = \frac{7}{11}\ \mu\text{F}
  5. So the answer is (b) 711 μF\frac{7}{11}\ \mu\text{F}.
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