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JEE Main 2013 (9 Apr, Shift 1) · Series LCR Circuit

Series LCR Circuit question from JEE Main 2013 (9 Apr, Shift 1)

Q59JEE Main 2013 · 9 APR · SHIFT 1Medium

Series LCR Circuit

In the circuit shown here, the voltage across L and C are respectively 300 V and 400 V. The voltage E of the ac source is:

Figure

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Answer: (c)

  1. Pure L–C series: VLV_L and VCV_C are 180∘180^\circ out of phase.
  2. E=∣VC−VL∣=∣400−300∣=100E = |V_C - V_L| = |400 - 300| = 100 V
  3. So the answer is (c) 100 V.
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