Physics Circle home Student Login

Home›Chapters›Alternating Current PYQs›Resonance, Bandwidth & Q Factor›Question 67

JEE Main 2023 (24 Jan, Shift 1) · Resonance, Bandwidth & Q Factor

Resonance, Bandwidth & Q Factor question from JEE Main 2023 (24 Jan, Shift 1)

Q67JEE Main 2023 · 24 JAN · SHIFT 1Easy

Resonance, Bandwidth & Q Factor

In the circuit shown in the figure, the ratio of the quality factor and the band width is ___________ s.

Figure

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 10

  1. From the figure: R=10 ΩR = 10\ \Omega, L=3.0L = 3.0 H, C=27 μC = 27\ \muF.
  2. Q=1RLC=110327×10−6=1003Q = \frac{1}{R}\sqrt{\frac{L}{C}} = \frac{1}{10}\sqrt{\frac{3}{27\times10^{-6}}} = \frac{100}{3}
  3. Bandwidth =RL=103 s−1= \frac{R}{L} = \frac{10}{3}\ \text{s}^{-1}
  4. QBW=10\frac{Q}{\text{BW}} = 10 s
Report a mistake

More questions on Resonance, Bandwidth & Q Factor