In the circuit shown in the following figure, the potential… | MHT CET 2024 (15 May, Shift 2)

Q35MHT CET 2024 · 15 MAY · SHIFT 2Medium

Combination of Capacitors

In the circuit shown in the following figure, the potential difference cross $3\ \mu\text{F}$ capacitor is

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Answer: (c)

The two cells oppose each other, so the net emf in the loop is $20 - 4 = 16$ V.
$3\ \mu\text{F}$ and $5\ \mu\text{F}$ are in series: $C_s = \frac{3\times 5}{8} = \frac{15}{8}\ \mu\text{F}$ .
$Q = C_s V = \frac{15}{8}\times 16 = 30\ \mu\text{C}$
$V_3 = \frac{Q}{3} = \frac{30}{3} = 10$ V
So the answer is (c) 10 V.

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